SOLUTION: I have been stuck on this question for about 45 minutes can somebody please help me? Problem :A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dim

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Question 771931: I have been stuck on this question for about 45 minutes can somebody please help me?
Problem :A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank? Thank You!

Found 3 solutions by Alan3354, nerdybill, Edwin McCravy:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank?
--------------
d = 2n
q = n+8
n+d+q = 44
----
n + 2n + n+8 = 44
4n+8 = 44
n = 9 nickels
18 dimes
17 quarters

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank?
.
Let q = number of quarters
then from "8 fewer nickels than quarters":
q-8 = number of nickels
and from "twice as many dimes as nickels"
2(q-8) = number of dimes
.
q + q-8 + 2(q-8) = 44
q + q-8 + 2q-16 = 44
4q -8 -16 = 44
4q -24 = 44
4q = 68
q = 16
.
amount in bank:
.25q + .05(q-8) + .10(2(q-8))
.25(16) + .05(16-8) + .10(2(16-8))
.25(16) + .05(8) + .10(2(8))
.25(16) + .05(8) + .10(16)
.25(16) + .05(8) + .10(16)
4 + .40 + 1.60
$6.00

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
I have been stuck on this question for about 45 minutes can somebody please help me?
Problem :A bank contains 44 coins (nickels, dimes, and quarters). There are twice as many dimes as nickels and 8 fewer nickels than quarters. How much money is in the bank? Thank You!

Alan didn't figure up the money, Nerdybill divided wrong and got 16
quarters instead of 17.

Let q = the number of quarters

>>,,,8 fewer nickels than quarters...<<
So the number of nickels is q-8

There are twice as many dimes as nickels
So the number of dimes is 2×(the number of nickels) = 2(q-8)

The equation comes from

%28matrix%284%2C1%2C%0D%0AThe%2Cnumber%2Cof%2Cquarters%29%29%22%22%2B%22%22%28matrix%284%2C1%2C%0D%0AThe%2Cnumber%2Cof%2Cnickels%29%29%22%22%2B%22%22%28matrix%284%2C1%2C%0D%0AThe%2Cnumber%2Cof%2Cdimes%29%29 %22%22=%22%22 %28matrix%285%2C1%2C%0D%0AThe%2Ctotal%2Cnumber%2Cof%2Ccoins%29%29

So 

 q + (q-8) + 2(q-8) = 44

q + q - 8 + 2q - 16 = 44 

            4q - 24 = 44

                 4q = 68

                  q = 17 quarters

the number of nickels is q-8 = 17-8 = 9 nickels

the number of dimes = 2(q-8) = 2(17-8) = 2(9) = 18 dimes

17 quarters = $0.25(17) = $4.25
 9 nickels  = $0.05(9)  =   .45
18 dimes    = $0.10(18) =  1.80
-------------------------------
 total money            = $6.50                             

Edwin