You can put this solution on YOUR website! Let n and n+2 the odd consecutive integers
Then:
(n+2)^2 = n(n+2)+34
n^2+4n+4 = n^2+2n+34
4n+4 = 2n+34
2n+4 = 34
2n = 30
n = 15
Answer: 15 and 17
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