SOLUTION: can someone please help me out? √x3 = 27 3√x2 = 9 i'm totally lost. thank you
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Algebra: Radicals -- complicated equations involving roots
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Question 77163
:
can someone please help me out?
√x3 = 27
3√x2 = 9
i'm totally lost. thank you
Answer by
checkley75(3666)
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You can
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SQRTX^3=27 SQUARE BOTH SIDES WE GET
X^3=27^2
X^3=3*3*3*3*3*3 NOW TAKE THE CUBE ROOT OF X^3 & 9^3
X=9 ANSWER
PROOF
SQRT9^3=27
SQRT(9^2*9)=27
SQRT(9^2*3^2)=27
9*3=27
27=27