Question 771429: Find the center of a circle using this equation x^2+y^2-10x-10y+25=0
Answer by Cromlix(4381)   (Show Source):
You can put this solution on YOUR website! The general equation of a circle
= x^2 + y^2 + 2gx + 2fy + c = 0
Centre = (-g,-f)
Therefore the equation of the circle:
x^2 + y^2 - 10x - 10y + 25 = 0
has (5,5) as the coordinates of its
centre.
Radius = square root of(g^2 + f^2 - c)
Square root of (5^2 + 5^2 - 25)
Square root of 25 + 25 - 25)
Square root of 25
= 5 units
Hope this helps.
:-)
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