SOLUTION: The product of 2 consecutive even integers is five thousand, one hundred two more than nine times their sum. What are the two integers?

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Question 771358: The product of 2 consecutive even integers is five thousand, one hundred two more than nine times their sum. What are the two integers?
Found 2 solutions by oscargut, Alan3354:
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!

Let n and n+4 those consecutive even numbers
n(n+4) = 5102+9(n+n+4)
n^2+4n = 18n+5138
n^2-14n -5138 = 0
This equation has no integer solutions , can you check the info please ?
I can help you with all of your questions at: mthman@gmail.com
Thanks

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!

n(n+2) = 5102 + 9*(n+n+2)
n^2+2n = 18n+5120
n^2-16n -5120 = 0
(n - 80)*(n + 64) = 0
--> 80 & 82
--> -64 & -62