SOLUTION: the perimeter of a rectangle is 24 units. Find all possible integet lengths and widths

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Question 771173: the perimeter of a rectangle is 24 units. Find all possible integet lengths and widths
Found 2 solutions by Jc0110, josgarithmetic:
Answer by Jc0110(165) About Me  (Show Source):
You can put this solution on YOUR website!
Let the length of the rectangle to be x and the width to be y.
2x%2B2y=24
2x%2F2%2B2y%2F2=24%2F2
x%2By=12 ... Find the two numbers which will sum up to 12
1%2B11=12
2%2B10=12
3%2B9=12
4%2B8=12
5%2B7=12
6%2B6=12
7%2B5=12
8%2B4=12
9%2B3=12
10%2B2=12
11%2B1=12
Therefore, the possible integer lengths, x are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and 11 whereas
the possible integer widths, y are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 and 11.

Answer by josgarithmetic(39616) About Me  (Show Source):
You can put this solution on YOUR website!
Just use meaning of perimeter, like r for rows, c for columns. Perimeter of 24 would be 2*r+2*c, and then you want all integer (really, natural numbers) values for r and c for which 2r+2c=24. You can use the simpler equation, r+c=12.
The question then becomes, which combinations of whole numbers will give you the sum of 12?