SOLUTION: Sorry not sure what kind of algebra it is. the question is from nov03 edexcel gcse paper, and tells us the area of a trapezium is 36cm^2 show that x^2-x-56=56, which i got to

Algebra ->  College  -> Linear Algebra -> SOLUTION: Sorry not sure what kind of algebra it is. the question is from nov03 edexcel gcse paper, and tells us the area of a trapezium is 36cm^2 show that x^2-x-56=56, which i got to       Log On


   



Question 77064: Sorry not sure what kind of algebra it is.
the question is from nov03 edexcel gcse paper, and tells us the area of a trapezium is 36cm^2
show that x^2-x-56=56, which i got to be,
1/2(a+b)h
=1/2(x+2+x+6)x-5
1/2(2x+8)x-5=36
x+4 multiplied by x-5
36 =x^2-20+4x-5
therefore x^2-x-56=0
is that right?
and then it asks you to solve the equation x^2-x-56=0
i've got so far
x^2-x=56
x^2=56+x
but i never know what to do next? please help!

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1)
In order to factor 1%2Ax%5E2%2B-1%2Ax%2B-56, first we need to ask ourselves: What two numbers multiply to -56 and add to -1? Lets find out by listing all of the possible factors of -56


Factors:

1,2,4,7,8,14,28,56,

-1,-2,-4,-7,-8,-14,-28,-56,List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to -56.

(-1)*(56)=-56

(-2)*(28)=-56

(-4)*(14)=-56

(-7)*(8)=-56

Now which of these pairs add to -1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -1

||||||||
First Number|Second Number|Sum
1|-56|1+(-56)=-55
2|-28|2+(-28)=-26
4|-14|4+(-14)=-10
7|-8|7+(-8)=-1
-1|56|(-1)+56=55
-2|28|(-2)+28=26
-4|14|(-4)+14=10
-7|8|(-7)+8=1
We can see from the table that 7 and -8 add to -1.So the two numbers that multiply to -56 and add to -1 are: 7 and -8 Now we substitute these numbers into a and b of the general equation of a product of linear factors which is: %28x%2Ba%29%28x%2Bb%29substitute a=7 and b=-8 So the equation becomes: (x+7)(x-8) Notice that if we foil (x+7)(x-8) we get the quadratic 1%2Ax%5E2%2B-1%2Ax%2B-56 again


%28x%2B7%29%28x-8%29=0
Now set each factor equal to zero
x%2B7=0
x=-7
x-8=0
x=8
So our answer is:
x=-7 or x=8
Since a negative answer doesn't work, the answer is x=8