For the equation  , 
perform the following:
a) Solve for all values of x that 
satisfies the equation.
 , 
perform the following:
a) Solve for all values of x that 
satisfies the equation. 
 Isolate the radical term by adding
Isolate the radical term by adding  to both sides
 to both sides
 Square both sides
 
Square both sides
 
 Get 0 on the right
Get 0 on the right
 Factor x out on the left
Factor x out on the left
 Use the zero-factor property
and set each of the factors
x and x-4 equal to 0.
Use the zero-factor property
and set each of the factors
x and x-4 equal to 0.
 gives answer as 0
 gives answer as 0
 gives another answer as 4
We must check these in the original
 gives another answer as 4
We must check these in the original
 
 
 
 So 0 checks
So 0 checks
 
 
 
 (((0=0)))
So 4 checks too.
b) Graph the functions y = x and 
y=2 SQRT of X on the same graph (by plotting 
points if necessary). Show the points of 
intersection of these two graphs.
The idea here is to take the equation
(((0=0)))
So 4 checks too.
b) Graph the functions y = x and 
y=2 SQRT of X on the same graph (by plotting 
points if necessary). Show the points of 
intersection of these two graphs.
The idea here is to take the equation
 and set y = to each side.
Then graph the two equations. Then the two 
values of y should be equal when the two sides 
of
 and set y = to each side.
Then graph the two equations. Then the two 
values of y should be equal when the two sides 
of  are equal, and that
will be where the graphs intersect.
Some points on
 are equal, and that
will be where the graphs intersect.
Some points on  are 
(-2,-2), (-1,-1) (2,2) (5,5)
Some points on
 are 
(-2,-2), (-1,-1) (2,2) (5,5)
Some points on  are 
(.5,1.4), (1,2), (3,3.5), (5,4.5)
 are 
(.5,1.4), (1,2), (3,3.5), (5,4.5)
 So we see that the blue curve and the green 
line intersect at (0,0) and (4,4) and the 
x-values are 0 and 4 at those points, which 
correspond to the algebraic solution for x 
above.
Edwin
So we see that the blue curve and the green 
line intersect at (0,0) and (4,4) and the 
x-values are 0 and 4 at those points, which 
correspond to the algebraic solution for x 
above.
Edwin