SOLUTION: solve. ln15+ln(2x-5)=7+ln3 help please.

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: solve. ln15+ln(2x-5)=7+ln3 help please.      Log On


   

Question 770527: solve.
ln15+ln(2x-5)=7+ln3
help please.
Found 2 solutions by Alan3354, josmiceli:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
ln15+ln(2x-5)=7+ln3
-----
ln(2x-5)=7 + ln3 - ln(15)
ln(2x-5) = ln(e^7) + ln(3) - ln(15)
ln(2x-5) = ln(3e^7/15)
2x-5 = 3e^7/15 = 3^7/5
2x = (e^7/5) + 5
x = ((e^7/5) + 5)/2
x =~ 112.1633

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+ln%28+15+%29+%2B+ln%28+2x+-+5+%29+=+7+%2B+ln%28+3+%29+
I can say:
+7+=+ln%28+e%5E7+%29+
+ln%28+15+%29+%2B+ln%28+2x+-+5+%29+=+ln%28+e%5E7+%29+%2B+ln%28+3+%29+
+ln%28+15%2A%28+2x+-+5+%29%29+=+ln%28+3%2Ae%5E7+%29+
Now I can say:
+15%2A%28+2x+-+5+%29+=+3%2Ae%5E7+
+30x+-+75+=+3e%5E7+
+30x+=+3e%5E7+%2B+75+
+x+=+.1%2Ae%5E7+%2B+2.5+