SOLUTION: {{{(x+1)(x+8)=-12}}}

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Question 77050This question is from textbook Glencoe Algebra 1
: %28x%2B1%29%28x%2B8%29=-12 This question is from textbook Glencoe Algebra 1

Found 2 solutions by jim_thompson5910, chitra:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2B1%29%28x%2B8%29=-12
x%5E2%2B9x%2B8=-12 foil the left side
x%5E2%2B9x%2B20=0 Add 12 to both sides
Solved by pluggable solver: Factoring Quadratics with a leading coefficient of 1 (a=1)
In order to factor 1%2Ax%5E2%2B9%2Ax%2B20, first we need to ask ourselves: What two numbers multiply to 20 and add to 9? Lets find out by listing all of the possible factors of 20


Factors:

1,2,4,5,10,20,

-1,-2,-4,-5,-10,-20,List the negative factors as well. This will allow us to find all possible combinations

These factors pair up to multiply to 20.

1*20=20

2*10=20

4*5=20

(-1)*(-20)=20

(-2)*(-10)=20

(-4)*(-5)=20

note: remember two negative numbers multiplied together make a positive number

Now which of these pairs add to 9? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 9

||||||
First Number|Second Number|Sum
1|20|1+20=21
2|10|2+10=12
4|5|4+5=9
-1|-20|-1+(-20)=-21
-2|-10|-2+(-10)=-12
-4|-5|-4+(-5)=-9
We can see from the table that 4 and 5 add to 9. So the two numbers that multiply to 20 and add to 9 are: 4 and 5 Now we substitute these numbers into a and b of the general equation of a product of linear factors which is: %28x%2Ba%29%28x%2Bb%29substitute a=4 and b=5 So the equation becomes: (x+4)(x+5) Notice that if we foil (x+4)(x+5) we get the quadratic 1%2Ax%5E2%2B9%2Ax%2B20 again


So the quadratic x%5E2%2B9x%2B20=0 factors to
%28x%2B4%29%28x%2B5%29=0
Set each factor equal to zero
x%2B4=0
x=-4
x%2B5=0
x=-5
So our answer is
x=-4 or x=-5
Answer by chitra(359) About Me  (Show Source):
You can put this solution on YOUR website!
The given expression is:

%28x%2B1%29%28x%2B8%29+=+-12+

Multiplying the two term, this can be written as:

%28x%5E2+%2B+8x+%2B+x+%2B+8+%29+=+-+12+


x%5E2+%2B+9x+%2B+8+%2B+12+=+0+

x%5E2+%2B+9x+%2B+20+=+0

20 can be factored as 5 * 4

x%5E2+%2B+5x+%2B+4x+%2B+20+=+0

%28x%28x+%2B+5%29+%2B+4%28x+%2B+5%29%29+=+0+

%28x+%2B+5%29%28x+%2B+4%29+=+0+


==> x + 5 = 0 OR x + 4 = 0

==> x = - 5 or x = -4

Hence, the solution.