SOLUTION: {{{5s-2s^2=0}}}
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Question 77048
This question is from textbook
Glencoe Algebra 1
:
This question is from textbook
Glencoe Algebra 1
Answer by
chitra(359)
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The given expression is:
Since, the term "s" is present in both the terms, we can take it as a common factor.
==> s = 0 or (5 - 2s) = 0
==> s = 0 or 5 = 2s
==> s = 0 or s =
Hence, the solution.