SOLUTION: Monday Roger goes to work, it takes him 35 minutes . Tuesday he goes to work and he goes 9 mph more than he did monday and it took him 7 minutes less. how far does he travel to wor

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Question 770399: Monday Roger goes to work, it takes him 35 minutes . Tuesday he goes to work and he goes 9 mph more than he did monday and it took him 7 minutes less. how far does he travel to work?
I Don't understand how to set up the problem. I tried making a chart that has distance rate and time .

Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
EDIT: Small change in first paragraph so explanation is more reliable.
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The question tells us that the distance to work is not known. Let's call d this distance to work number. We partial information about amount of time to reach work.

WHEN__________rate___________time hours_________distance
Monday________(__)___________35/60______________d
Tuesday_______(__)___________28/60______________d

We do not really know the traveling rates on those days either. We only were given a difference in rate between the days, so we could use r, rate used on Monday. Tuesday was used as 9 mph more than Monday:

WHEN__________rate___________time hours_________distance
Monday________(r)______________35/60______________d
Tuesday_______(r+9)___________28/60______________d

Next, we use the basic concept of rate, r*t=d, rate times time equals distance. The distances of each day are equal.

Monday, d=r%2A%2835%2F60%29
Tuesday, d=%28r%2B9%29%2A%2828%2F60%29

highlight%28r%2835%2F60%29=%28r%2B9%29%2828%2F60%29%29
Reaching this equation, whether the time hour fractions reduced or not, is MOST of the solution. SOLVING for r is fairly straightforward algebra skills. Use the value to find distance d=r%2A%2835%2F60%29 or d=r%287%2F12%29.