SOLUTION: if sin A=2.511x, cos A=3.06x and sin 2A=3.939x, find the value of x?

Algebra ->  Trigonometry-basics -> SOLUTION: if sin A=2.511x, cos A=3.06x and sin 2A=3.939x, find the value of x?      Log On


   

Question 770308: if sin A=2.511x, cos A=3.06x and sin 2A=3.939x, find the value of x?
Answer by lwsshak3(11628) About Me  (Show Source):
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if sin A=2.511x, cos A=3.06x and sin 2A=3.939x, find the value of x?
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sin2A=2sinAcosA
3.939x=2*2.511x*3.06x=15.367x^2
15.367x^2-3.939x=0
x(15.367x-3.939)=0
x=0
or
x=3.939/15.367≈0.256