SOLUTION: evaluate arc cot [2cos(arc sin .5)]
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Question 770304
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evaluate arc cot [2cos(arc sin .5)]
Answer by
lwsshak3(11628)
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evaluate arc cot [2cos(arc sin .5)]
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arc sin .5=30º
cos 30º=√3/2
2cos(arc sin .5)=2*√3)/2=√3
arc cot [2cos(arc sin .5)]= arc cot √3)=arc tan(1/√3)=30º