SOLUTION: Raju has three boxes, whose total weight is {{{60&1/2}}} kg. If box B is {{{3&1/2}}} kg more than box A while box C weighs {{{5&1/3}}} kg more than Box B, find the weight of box A.

Algebra ->  Equations -> SOLUTION: Raju has three boxes, whose total weight is {{{60&1/2}}} kg. If box B is {{{3&1/2}}} kg more than box A while box C weighs {{{5&1/3}}} kg more than Box B, find the weight of box A.      Log On


   

Question 770255: Raju has three boxes, whose total weight is 60%261%2F2 kg. If box B is 3%261%2F2 kg more than box A while box C weighs 5%261%2F3 kg more than Box B, find the weight of box A.
Answer by Jc0110(165) About Me  (Show Source):
You can put this solution on YOUR website!
Let the weight of box A to be a, of box B to be b and of box C to be c.
Box B is 3%261%2F2 kg more than box A means b=a%2B3%261%2F2.
Box C weighs 5%261%2F3 kg more than Box B means c=b%2B5%261%2F3.
The total weight of three boxes is 60%261%2F2 kg means a%2Bb%2Bc=60%261%2F2.
a%2Bb%2Bc=60%261%2F2 --> Equation 1
b=a%2B3%261%2F2
a=b-3%261%2F2 --> Equation 2 ... Substitute a=b-3%261%2F2 into Equation 1
c=b%2B5%261%2F3 --> Equation 3 ... Substitute c=b%2B5%261%2F3 into Equation 1
a%2Bb%2Bc=60%261%2F2
%28b-3%261%2F2%29%2Bb%2B%28b%2B5%261%2F3%29=60%261%2F2
b-3%261%2F2%2Bb%2Bb%2B5%261%2F3=60%261%2F2
b%2Bb%2Bb-3%261%2F2%2B5%261%2F3=60%261%2F2
3b-3%261%2F2%2B5%261%2F3=60%261%2F2
3b%2B1%265%2F6=60%261%2F2
3b=60%261%2F2-1%265%2F6
3b=58%262%2F3
3b=176%2F3
cross%283%29b%2Fcross%283%29=%28176%2F3%29%2F3
b=%28176%2F3%29%2A%281%2F3%29
b=176%2F9
b=19%265%2F9 ... Substitute b=19%265%2F9 into Equation 2
a=b-3%261%2F2
a=19%265%2F9-3%261%2F2
a=16%261%2F18
Therefore, the weight of box A is 16%261%2F18 kg.