SOLUTION: Hi, I`m trying to study some of last years math to keep my mind fresh. I have forgotten some of this material and was wondering if you could help me solve this problem : "Janet wal

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Question 770137: Hi, I`m trying to study some of last years math to keep my mind fresh. I have forgotten some of this material and was wondering if you could help me solve this problem : "Janet walked to school at 6 km/h and rode home from school at a speed 3 times as fast. If her total traveling time was 1 hour, how many minutes did she spend walking?" I tried making several different charts, none with success, or at least that make sense to me. Could you please help me? Thanks a lot! :)
Found 2 solutions by ramkikk66, MathTherapy:
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Walking speed = 6 km/h
Riding speed = 3 times = 18 km/h
Let distance to school be x km
Time taken to walk to school = x/6 hours (because time = distance / speed)
Time taken to ride back = x/18 hours
Total time is given to be 1 hour
So we get the equation
x%2F6+%2B+x%2F18+=+1
Simplifying
3%2Ax+%2B+x+=+18
4%2Ax+=+18
x+=+4.5 km
Distance to school is 4.5 km
Since she walked at 6 kph, how much time did she spend walking? it is
Distance / speed = 4.5/6 = 0.75 hours or 45 minutes.
:)

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
Hi, I`m trying to study some of last years math to keep my mind fresh. I have forgotten some of this material and was wondering if you could help me solve this problem : "Janet walked to school at 6 km/h and rode home from school at a speed 3 times as fast. If her total traveling time was 1 hour, how many minutes did she spend walking?" I tried making several different charts, none with success, or at least that make sense to me. Could you please help me? Thanks a lot! :)

Let time she spent walking be T
Then time spent riding = 1 – T
Since walking speed = 6 km/h, then distance covered walking = T(6), or 6T km
Since riding speed = 18 (3 * 6) km/h, then distance covered riding = 18(1 - T), or 18 – 18T

Distance covered walking, equals distance covered riding, OR
6T = 18 – 18T
6T + 18T = 18
24T = 18
T, or time spent walking = 18%2F24, or 3%2F4 hour, or highlight_green%2845%29 minutes

You can do the check!!

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