SOLUTION: 2x^3+3x^2-2x=? I know that I need to factor, but when it comes to cubes, I get confused.

Algebra ->  Rational-functions -> SOLUTION: 2x^3+3x^2-2x=? I know that I need to factor, but when it comes to cubes, I get confused.      Log On


   

Question 76992: 2x^3+3x^2-2x=?
I know that I need to factor, but when it comes to cubes, I get confused.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
In this case we have a common factor of x, so we can factor out an x
2x%5E3%2B3x%5E2-2x
x%282x%5E2%2B3x-2%29
Now we can factor the quadratic in the parenthesis
ERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'quadratic_factoring'.
Error occurred executing solver 'quadratic_factoring' .


So the quadratic in the parenthesis factors to this:
%282x-1%29%28x%2B2%29
Now our factored polynomial looks like this

x%28%282x-1%29%28x%2B2%29%29
Notice if we foil the terms and distribute the x we get 2x%5E3%2B3x%5E2-2x again