SOLUTION: I'll seriously love you forever if you help me. :'( SQRT(4a + 1) = 1 CUBERT(3x - 8) = 1 SQRT(x + 4) = SQRT(x) - 2 Assume that a surve

Algebra ->  Inequalities -> SOLUTION: I'll seriously love you forever if you help me. :'( SQRT(4a + 1) = 1 CUBERT(3x - 8) = 1 SQRT(x + 4) = SQRT(x) - 2 Assume that a surve      Log On


   



Question 769865: I'll seriously love you forever if you help me. :'(

SQRT(4a + 1) = 1




CUBERT(3x - 8) = 1




SQRT(x + 4) = SQRT(x) - 2




Assume that a surveyor stands at the top of a mountain that is "h" feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
SQRT(4a + 1) = 1
square both sides of equation4a+1=1
4x=1-1
4a=0
a=0




CUBERT(3x - 8) = 1

square both sides
3x-8 =1
3x=8
x=8/3



SQRT(x + 4) = SQRT(x) - 2

square both sides
x+4 = x-4sqrt(x)+4

x=0



Assume that a surveyor stands at the top of a mountain that is "h" feet tall. If the distance (in feet) that he can see is defined by d = 3200.2 SQRT(h), then answer the following. (a) How far can the surveyor see from the top of a 2000-foot mountain? (b) How tall is the mountain, if the surveyor can see 15 miles? (Note: 1 mile equals 5280 feet.)


its is substitution problem