SOLUTION: A box contains five red balls, six green balls, and two white balls. Three balls are drawn, but each one is not replaced before the next one is drawn. Find the probability the fi
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Question 769765: A box contains five red balls, six green balls, and two white balls. Three balls are drawn, but each one is not replaced before the next one is drawn. Find the probability the first is red, the second is green, and the third is white. Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Work:
(5/13)(6/12)(2/11)
= 5/143
Answer: 5/143
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