SOLUTION: Please help me and provide explanation to understand further, Uniform Motion Because of bad weather, a bus driver reduced the usual speed along a 150-mile bus route by 10 mph

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Question 769626: Please help me and provide explanation to understand further,
Uniform Motion
Because of bad weather, a bus driver reduced the usual speed along a 150-mile bus route by 10 mph. The bus arrived only 30 minutes later than its usual arrival time. How fast does the bus usually travel?

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
Because of bad weather, a bus driver reduced the usual speed along a 150-mile bus route by 10 mph. The bus arrived only 30 minutes later than its usual arrival time. How fast does the bus usually travel?
Ans:
Let the bus' normal speed be x mph.
Normal time taken to cover 150 miles = 150/x hours (since time = distance / speed)
If he reduces the speed by 10 mph, the new speed = x - 10
Time taken at the slower speed = 150/(x - 10) hours
It is given that the new time is 0.5 hours (30 minutes) more than the normal 
time.
So we get the equation
150%2F%28x+-+10%29+=+150%2Fx+%2B+0.5
150%2Ax+=+150%2A%28x+-+10%29+%2B+0.5%2Ax%2A%28x+-+10%29
150%2Ax+=+150%2Ax+-+1500+%2B+0.5%2Ax%5E2+-+5%2Ax
0.5%2Ax%5E2+-+5%2Ax+-+1500+=+0 or
x%5E2+-+10%2Ax+-+3000+=+0
This is a standard quadratic equation which can be solved through factorization
%28x+-+60%29%2A%28x+%2B+50%29+=+0
The two solutions are:
x - 60 = 0 i.e. x = 60
x + 50 = 0 i.e. x = -50
Since x cannot be negative, x = 60
Normal speed = highlight%2860%29 mph
Check for correctness:
At normal speed, time taken = 150/60 = 2.5 hours
Reduced speed = 60 - 10 = 50
Time taken at 50 mph = 150/50 = 3 hours which is 30 minutes more than 2.5 hrs!
So the answer is correct. Hope you got it :)