SOLUTION: The one-to-one function is defined by f(x)=6x/(7x-2) . Find f^-1 , the inverse of f . Then, give the domain and range of f^-1 using interval notation.

Algebra ->  Inverses -> SOLUTION: The one-to-one function is defined by f(x)=6x/(7x-2) . Find f^-1 , the inverse of f . Then, give the domain and range of f^-1 using interval notation.      Log On


   

Question 769513: The one-to-one function is defined by
f(x)=6x/(7x-2)
.
Find f^-1 , the inverse of f . Then, give the domain and range of f^-1 using interval notation.
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
y=6x/(7x-2)
y(7x-2)=6x
7xy-2y=6x
7xy-6x=2y
x(7y-6)=2y
x=2y/(7y-6)
Inv(f(x))=2x/(7x-6)
dom(Inv(f(x))=(-oo,6/7)U(6/7,oo)
ran(Inv(f(x))=(-oo,oo)