SOLUTION: cos2x-cos6x=0 find the exact values of all solutions between 0 and pie

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Question 769469: cos2x-cos6x=0 find the exact values of all solutions between 0 and pie
Answer by tommyt3rd(5050) About Me  (Show Source):
You can put this solution on YOUR website!
cos2x-cos6x=0
cos2x+=+cos6x
so
6x+=+2pi%2An%2B-+2x
then for 0%3Cx%3Cpi
we get
pi%2F4,pi%2F2, %283pi%29%2F4