SOLUTION: Coffee costs $12 per case and tea costs $8 per case. If an order comes in for a total of 250 cases for $2,600, what was the specific number of cases of tea? Word problems are t

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Coffee costs $12 per case and tea costs $8 per case. If an order comes in for a total of 250 cases for $2,600, what was the specific number of cases of tea? Word problems are t      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 769337: Coffee costs $12 per case and tea costs $8 per case. If an order comes in for a total of 250 cases for $2,600, what was the specific number of cases of tea?
Word problems are the most difficult for me. :-(
Thank you!
Linda

Found 2 solutions by mananth, josmiceli:
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
x= Coffee cases
y= Tea cases
First condition -number of cases
1 x + 1 y = 250 .............1
Total value
12 x + 8 y = 2600 .............2
Eliminate y
multiply (1)by -8
Multiply (2) by 1
-8 x -8 y = -2000
12 x + 8 y = 2600
Add the two equations
4 x = 600
/ 4
x = 150
plug value of x in (1)
1 x + 1 y = 250
150 + y = 250
y = 250 -150
y = 100
y = 100
x= 150 Coffee cases
y= 100 Tea cases
m.ananth@hotmail.ca

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +c+ = number of cases of coffee
Let +t+ = number of cases of tea
--------------
(1) +c+%2B+t+=+250+
(2) +12c+%2B+8t+=+2600+
---------------------
Multiply both sides of (1) by +8+
and subtract (1) from (2)
(2) +12c+%2B+8t+=+2600+
(1) +-8c+-+8t+=+-2000+
+4c+=+600+
+c+=+150+
and, since
(1) +c+%2B+t+=+250+
(1) +150+%2B+t+=+250+
(1) +t+=+100+
150 = number of cases of coffee
100 = number of cases of tea
--------------------------
check:
(2) +12c+%2B+8t+=+2600+
(2) +12%2A150+%2B+8%2A100+=+2600+
(2) +1800+%2B+800+=+2600+
(2) +2600+=+2600+
OK