SOLUTION: Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second      Log On


   



Question 769313: Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second day than on the first day, how many did he buy each day and at what price per ball?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Last week Al bought some golf balls for $20. The next day they were on sale for $0.50 per ball less, and he bought $22.50 worth of balls. If he purchased 5 more balls on the second day than on the first day, how many did he buy each day and at what price per ball?
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Let original purchase be "x" balls at $20
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Next day value of the ball he bought was [(2000/x)-50)(x+5) = 2250
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Solve for "x":
(2000-50x)(x+5) = 2250x
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2000x + 10000 - 50x^2 - 250x = 2250x
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50x^2 +500x - 10000 = 0
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x^2 + 10x - 200 = 0
(x+20)(x-10) = 0
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Positive solution:
x = 10 (# purchased on 1st day)
x+5 = 15 (# purchased on 2nd day)
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Cheers,
Stan H.
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