You can
put this solution on YOUR website!
cos(u+v)cos(v) + sin(u+v)sin(v) = cos(u)
Remembering the identity
cos(A-B) = cos(A)cos(B) + sin(A)sin(B)
we recognize that the left side,
cos(u+v)cos(v) + sin(u+v)sin(v)
is simply cos(A)cos(B) + sin(A)sin(B)
with u+v substituted for A and v substituted for B.
we have
cos[(u+v)-v]
cos(u+v-v)
cos(u)
Edwin