SOLUTION: find the x-intercept of the parabola with vertex(-1,-17) and y intercept (0,-13). write your answer in this form (x1,y1) (x2,y2)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the x-intercept of the parabola with vertex(-1,-17) and y intercept (0,-13). write your answer in this form (x1,y1) (x2,y2)      Log On


   



Question 769193: find the x-intercept of the parabola with vertex(-1,-17) and y intercept (0,-13). write your answer in this form (x1,y1) (x2,y2)
Answer by lwsshak3(11628) About Me  (Show Source):
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find the x-intercept of the parabola with vertex(-1,-17) and y intercept (0,-13). write your answer in this form (x1,y1) (x2,y2)
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Standard form of equation for a parabola: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of vertex, A=coefficient that affects the slope or steepness of the curve
..
solve for A using given coordinates of the vertex (-1,-17) and y-intercept (0,-13)
y=A(x-h)^2+k
-13=A(0+1)^2-17
-13=A-17
A=4
Equation of given parabola:
y=4(x-h)^2+k
to find x-intercepts set y=0
0=4(x+1)^2-17
4(x+1)^2=17
(x+1)^2=17/4
take sqrt of both sides
x+1=±√17/2
x=-1±√17/2
x≈-3.06
or
x≈1.06
x-intercepts: (-3.06,0) and (1.06,0)