Question 76904: Hi, I'm not sure if I chose the right topic, but anyways, I need help on a problem with a really strange equation. The problem states this: An object is thrown up into the air at a rate of 24 meters per second from a height of 2 meters. Given that the acceleration due to gravity is -9.8 meters per second squared, write an eqaution for the height of the object, h, in terms of the number of seconds since the object was thrown, t.
My teacher said to use this formula to write my eqaution: h=1/2gt^2+vt+h^0. The ^0 part of the eqaution is actually underneath the right hand side of the h, kind of like an underscore 0. I tried to plug in the numbers, but it did not come out right. I did: h=1/2(-9.8)t^2+24t+2. I was not sure what the underscore zero meant, so I left it out. Could you please help me write my equation? Thanks.
Found 2 solutions by scott8148, jim_thompson5910:
Answer by scott8148(6628)   (Show Source):
You can put this solution on YOUR website! you have written the correct equation
the 0 by the h is a subscript...usually read as "h sub zero"...this is the starting height (when time is zero)
Answer by jim_thompson5910(35256)  (Show Source):
You can put this solution on YOUR website! It looks like you did that right. Your function (the height function) is going to be in terms of t. In other words, if you plug in a time, you get a height at time t. The last term  is simply another h (not the h on the left side), where the subscript of zero means its our original value. So in this case  , or our original height is 2 meters.
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