Question 769015: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.If
csc θ = −2
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
If csc θ = −2, sin(theta) = -1/2
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Reference angle is pi/6
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Since the sin is negative theta is in QIII or QIV.
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Theta = p + pi/6 = (7/6)pi
OR
Theta = (2pi)-(pi/6) = (11/6)pi
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Cheers,
Stan H.
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