SOLUTION: A triangle has legs that measure 3 feet, 5 feet, and 7 feet. Calculate the dimensions of a similar triangle whose longest side measures 13 inches

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Question 768954: A triangle has legs that measure 3 feet, 5 feet, and 7 feet. Calculate the dimensions of a similar triangle whose longest side measures 13 inches

Found 2 solutions by lwsshak3, josmiceli:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
A triangle has legs that measure 3 feet, 5 feet, and 7 feet. Calculate the dimensions of a similar triangle whose longest side measures 13 inches
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7 ft=84 inches
multiply each dimension by 13/84:
13/84( 3 feet, 5 feet, and 7 feet)=(39/84 ft, 65/84 ft, 91/84 ft)=(5.57 inches, 9.29 inches, 13 inches)
dimensions of a similar triangle in inches: 5.57 by 9.29 by 13

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If you place the 2nd triangle so that the
13" side is parallel to the 7' side
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Call the side of the 2nd triangle that is
parallel to the 3' side +a+
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Call the side of the 2nd triangle that is
parallel to the 5' side +b+
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Now I can say:
+a+%2F+3+=+13%2F7%0D%0A%7B%7B%7B+7a+=+3%2A13+
+a+=+39%2F7+
+a+=+5.571+
and
+b+%2F+5+=+13%2F7+
+7b+=+5%2A13+
+7b+=+65+
+b+=+9.286+
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The dimensions are:
5.571"
9.286"
13"
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check:
+5.571+%2F+9.286+=+3+%2F+5+
+5%2A5.571+=+3%2A9.286+
+27.855+=+27.858+
close enough