SOLUTION: The polynomial 0.0049x^3+0.0053x^2+0.191x+1.12 gives the approximate total earnings of a company, in millions of dollars, where x represents the number of years since 1996. This mo
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-> SOLUTION: The polynomial 0.0049x^3+0.0053x^2+0.191x+1.12 gives the approximate total earnings of a company, in millions of dollars, where x represents the number of years since 1996. This mo
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Question 768859: The polynomial 0.0049x^3+0.0053x^2+0.191x+1.12 gives the approximate total earnings of a company, in millions of dollars, where x represents the number of years since 1996. This model is valid for the years from 1996 to 2000. Determine the earnings for 2000. Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! The polynomial 0.0049x^3+0.0053x^2+0.191x+1.12 gives the approximate total earnings of a company, in millions of dollars, where x represents the number of years since 1996. This model is valid for the years from 1996 to 2000. Determine the earnings for 2000.
year 2000 (x=4)
Earning for 2000 is:
0.0049(4^3)+0.0053(4^2)+0.191(4)+1.12 = 2.2824
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