SOLUTION: I have not only spent the last four days, literally, on one assignment consisting of 7 sections all having to do with natural log, e, 10 and log.
But anyhow, this one I have spent
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: I have not only spent the last four days, literally, on one assignment consisting of 7 sections all having to do with natural log, e, 10 and log.
But anyhow, this one I have spent
Log On
Question 768771: I have not only spent the last four days, literally, on one assignment consisting of 7 sections all having to do with natural log, e, 10 and log.
But anyhow, this one I have spent more than ten hours on by itself.
Write the expression as a logarithm of a single expression.
ln sqrt5 - ln25.
I have broke it down some, as far as I can get it: 5 ln^1/2 - ln 5 - ln 5.
I'm not entirely sure I understand how I got here.
But the answer in the book say's It's -3/2 ln 5=ln 5^-3/2
Were does the -3/2come from and how do I set this up Found 2 solutions by lwsshak3, ramkikk66:Answer by lwsshak3(11628) (Show Source):
It's fairly simple if you remember the basic rules of logarithms.
1) Log a - log b = log (a/b) --> assume it is all to the same base e.g. ln.
2) log a + log b = log (a * b)
3) log (a^b) = b * log a
Now look at the problem.
= --> from rule 1 above
Call this eqn (A)
Now look at what you have inside the brackets. =
= -----> remember that (a^m)/(a^n) = a^(m - n)
=
Now going back to eqn A
=
= ------> from rule 3 above
Hope you got it now. Let me know if it is not clear :)
(
