SOLUTION: Find the solution set: x^3+x^2-7x-3 Hint: the possible rational roots are factors of 3
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Question 768727
:
Find the solution set:
x^3+x^2-7x-3
Hint: the possible rational roots are factors of 3
Answer by
josgarithmetic(39620)
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The request implies the cubic expression is equated to 0.
Checking the root, -3 with synthetic division, the quotient is x^2-2x-1. The REAL and rational root is x=-3.
The synthetic division supporting this is:
-3___|____1____1____-7____-3
_____|____ ___-3____6_____3
_____|______________________
__________1___-2____-1____0----------see, the remainder is 0.
If you work further with the resulting quadratic, you'll find the irrational roots
and
.