SOLUTION: (write a equation for each condition listed) 1.the line with the slope of -8 and a y-intercept of 3 (in slope-intercept form) 2.the line that passes through (-2,0)and has a

Algebra ->  Linear-equations -> SOLUTION: (write a equation for each condition listed) 1.the line with the slope of -8 and a y-intercept of 3 (in slope-intercept form) 2.the line that passes through (-2,0)and has a      Log On


   



Question 768529: (write a equation for each condition listed)

1.the line with the slope of -8 and a y-intercept of 3 (in slope-intercept form)
2.the line that passes through (-2,0)and has a slope of 5 (in point-slope form)
3.the horizontal line that passes through (-2,6)
4.the vertical line that passes through (-2,6)

If you guys at algebra.com can help me solve these problems it would be highly appreciated it?
thanks Troy

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!

1.the line with the slope of -8 and a y-intercept of 3 (in slope-intercept form)
2.the line that passes through (-2,0)and has a slope of 5 (in point-slope form)
3.the horizontal line that passes through (-2,6)
4.the vertical line that passes through (-2,6)
Ans:
1)
Equation of a line with slope m and y-intercept c is given by y = m*x + c
Here slope = -8, y-intercept = 3
So eqn is y+=+-8%2Ax+%2B+3 or 8%2Ax+%2B+y+-+3+=+0
2)
Eqn of a line that passes through x1,y1 and has slope m is given by
%28y+-+y1%29+=+m%2A%28x+-+x1%29
Here, (x1,y1) = (-2,0) and slope = 5
%28y+-+0%29+=+5%2A%28x+-+%28-2%29%29
y+=+5%2Ax+%2B+10 or 5%2Ax+-+y+%2B+10+=+0 is the equation
3)
Horizontal line has the equation of the form y =
Since it passes through (-2,6), one value of y, which is the constant value,
has to be 6.
So, the equation is y+=+6
4)
Vertical line has the equation of the form x =
Since it passes through (-2,6), one value of x, which is the constant value,
has to be -2.
So, the equation is x+=+-2 or x+%2B+2+=+0
Hope you got it :)