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| Question 768365:
 
 Identify the vertex, focus, and directrix of the graph
 y=1/20(x-3)^2-3
 Is the following correct:
 Vertex (3,-3)
 Focus (3,2)
 Directix = -8
 
 
 
 
 
 
 
 
 Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! Identify the vertex, focus, and directrix of the graph y=1/20(x-3)^2-3
 (y+3)=(x-3)^2/20
 (x-3)^2=20(y+3)
 This is an equation of a parabola that opens upward.
 Its basic form: (x-h)^2=4p(y-k), (h.k)=(x,y) coordinates of the vertex
 For given parabola:
 vertex: (3,-3)
 axis of symmetry: x=3
 4p=20
 p=5
 focus: (3,2) (p-units above vertex on the axis of symmetry)
 directrix: y=-8 (p-units below vertex on the axis of symmetry)
 congratulations! you got all the answers correct
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