SOLUTION: the difference of the areas of 2 squares is 75 square feet. each side of the larger square is twice the length of a side of the smaller square. find the length of the side of each

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Question 768337: the difference of the areas of 2 squares is 75 square feet. each side of the larger square is twice the length of a side of the smaller square. find the length of the side of each square.
Answer by ramkikk66(644) About Me  (Show Source):
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the difference of the areas of 2 squares is 75 square feet. each side of the larger square is twice the length of a side of the smaller square. find the length of the side of each square.

Ans:

Let the smaller square be of side x

Then the larger square has each side of 2*x

Area of smaller square = x%5E2

Area of larger square = %282%2Ax%29%5E2+=+4%2Ax%5E2

Difference in areas = 4%2Ax%5E2+-+x%5E2+=+75

Simplifying

3%2Ax%5E2+=+75

x%5E2+=+25

x+=+5

So the two squares have sides as highlight%285%29 and highlight%2810%29 feet.

Check for correctness.

Area of first = 5*5 = 25

Area of second = 10*10 = 100

Difference = 100 - 25 = 75 

Correct :)