SOLUTION: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
Algebra ->
Trigonometry-basics
-> SOLUTION: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
Log On
You can put this solution on YOUR website! Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
csc θ = − 2√3/3
sinθ=1/cscθ=-3/2√3=-3√3/6=-√3/2
θ=4π/3 and 5π/3 (in Q3 and Q4 where sin and csc are<0)
(