SOLUTION: I need help solving...totally lost on this one =( Solve for the inverse: g(x)=2x divided by x-3.

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Question 768292: I need help solving...totally lost on this DISABLED_event_one= (
Solve for the inverse: g(x)=2x divided by x-3.
Found 2 solutions by josgarithmetic, solver91311:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
g%28x%29=2x%2F%28x-3%29
You want g%5E-1%28x%29 so that g%5E-1%28g%28x%29%29=g%28g%5E-1%28x%29%29=x

g%28g%5E-1%28x%29%29=2%28g%5E-1%28x%29%29%2F%28%28g%5E-1%28x%29%29-3%29=x

Temporarily substitute y=g%5E-1%28x%29;
2y%2F%28y-3%29=x
2y=x%28y-3%29
2y=xy-3x
2y-xy=-3x
y%282-x%29=-3x
y=-3x%2F%282-x%29
highlight%28g%5E-1%28x%29=3x%2F%28x-2%29%29

and you can check if g(x) really works in g^-1(x) to produce x.

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!




















John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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