You can put this solution on YOUR website! Solve the equation:
log(x^2+3)=log(x+6)
I started by dividing both sides with (x+6)
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arguments of logs to the same base are equal to each other.
x^2+3=x+6
x^2-x-3=0
solve for x by quadratic formula:
a=1, b=-1, c=-3
x=[-(-1)±√(-1)^2-4*1*-3)]2*1
x=[1±√(1+12)]/2
x=[1±√13]/2
x≈2.033
or
x≈-1.303
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