SOLUTION: Find two values of &#952;, 0 &#8804; &#952; < 2&#960;, that satisfy the given trigonometric equation. sec &#952; = &#8722;2

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Question 768115: Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
sec θ = −2

Answer by lwsshak3(11628) About Me  (Show Source):
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Find two values of θ, 0 ≤ θ < 2π, that satisfy the given trigonometric equation.
sec θ = −2
cosθ=1/secθ=-1/2
θ=2π/3 and 4π/3 (In Q2 and Q3 where cos and sec are<0)