SOLUTION: Please help.
The length of a rectangle is 2 ft longer than the width. If the area is 16 ft^2, then what are the length and width?
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The length of a rectangle is 2 ft longer than the width. If the area is 16 ft^2, then what are the length and width?
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Question 76810: Please help.
The length of a rectangle is 2 ft longer than the width. If the area is 16 ft^2, then what are the length and width? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! x(x+2)=16
x^2+2x-16=0
using the quadratic equation we get:
X=(-2+-SQRT[2^2-4*1*-16])/2*1
X=(-2+-SQRT[4+64])/2
X=(-2+-SQRT68)/2
X=(-2+-8.246)/2
X=(-2+8.246)/2
X=6.246/2
X=3.123 ANSWER FOR THE SHORT SIDE.
3.123+2=5.123 ANSWER FOR THE LONG SIDE.
PROOF
3.123*5.123=16
16=16
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