SOLUTION: * help me please. i don't even know where to begin The graph of y = SQRT(x3 - x) contains which point? A (3, 24) B(0, 1) C(1, 1) D(2, 6) E (4, 2SQRT(15)) F none o

Algebra ->  Systems-of-equations -> SOLUTION: * help me please. i don't even know where to begin The graph of y = SQRT(x3 - x) contains which point? A (3, 24) B(0, 1) C(1, 1) D(2, 6) E (4, 2SQRT(15)) F none o      Log On


   

Question 768068: * help me please. i don't even know where to begin
The graph of y = SQRT(x3 - x) contains which point?
A (3, 24)
B(0, 1)
C(1, 1)
D(2, 6)
E (4, 2SQRT(15))
F none of the above

The graph of y = (x4 + 4x3 - x)(1/4) contains which point?
A (4,2)
B(-2,0)
C(-4, SQRT(2))
D(2, 2(1/4) )
E (2,0)
F (3,4)
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The graph of y = SQRT(x3 - x) contains which point?
Try the value given for x, see if it equals the value given for y
The first one 3, 24
y+=+sqrt%283%5E3-3%29
y+=+sqrt%2827-3%29
y+=+sqrt%2824%29
the square root of 24 is between 4 and 5, so this is not the answer
:
Do the same with each answer
E is the correct one, where x = 4
y+=+sqrt%284%5E3-4%29
y+=+sqrt%2864-4%29
y+=+sqrt%2860%29
factor inside the radical to reveal a perfect square (4)
y+=+sqrt%284%2A15%29
extract the square root of that and you have
y+=+2%2Asqrt%2815%29
:
I am not sure about this 2nd equation, does not make sense