Question 767604: A father is twice as old as his son 12 years ago the father was 4 times as old as the son was then - determine the present age Answer by anukamal(7) (Show Source):
You can put this solution on YOUR website! Let the son's present age be x years
then father's age is 2x years.
12 years ago,
The son's age is 2(x-12)=4(x-12)
2x-24=4x-48
2x-4x=-48+24
-2x=-24
therefore x=12
Son's age is 12 years
Father's age is 24 years
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