SOLUTION: i''m having trouble understanding how these problems work this is the problem.. S = 12.75 e^(-0.0425 t). When S=7.35, find t. i dont know were to start can you please help me

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: i''m having trouble understanding how these problems work this is the problem.. S = 12.75 e^(-0.0425 t). When S=7.35, find t. i dont know were to start can you please help me      Log On


   



Question 767375: i''m having trouble understanding how these problems work this is the problem.. S = 12.75 e^(-0.0425 t). When S=7.35, find t. i dont know were to start can you please help me
Found 2 solutions by Cromlix, solver91311:
Answer by Cromlix(4381) About Me  (Show Source):
You can put this solution on YOUR website!
S = 12.75 e^-0.0425t
Find t when S = 7.35
S = 12.75 e^-0.0425t
7.35 = 12.75 e^-0.0425t
7.35/12.75 = e^-0.0425t
0.57647 = -0.0425t e
log e both sides
(Notice how the -0.0425t comes in front of e)
loge 0.57647 = -0.0425t loge e
(loge e = 1)
loge 0.57647/-0.0425 = t
t = 12.96
Hope this helps.
:-)

Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!






Take the natural log of both sides:



Use



to write



Use



to write



The rest is just a little algebra



John

Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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