SOLUTION: Solve the following equation approximately for 0≤θ≤2Π with θ in radians. -7sin(2θ-4) = 2

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Question 767215: Solve the following equation approximately for 0≤θ≤2Π
with θ in radians.
-7sin(2θ-4) = 2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve the following equation approximately for 0≤θ≤2Π
with θ in radians.
-7sin(2θ-4) = 2
sin(2θ-4) =-2/7
2θ-4≈6
2θ≈10
θ≈5 radians