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64s6+t6
That's the sum of two cubes:
64s6 is equal to (4s2)3
t6 is equal to (t2)3
The sum of two cubes A3+B3 factors as (A+B)(A2-AB+B2)
(A+B)(A2-AB+B2)
let A = 4s2, B = t2
(A+B)(A2-AB+B2) = (4s2+t2)[(4s2)2-(4s2)(t2)+(t2)2] =
(4s2+t2)[16s4-4s2t2+t4]
(4s2+t2)(16s4-4s2t2+t4)
Edwin