SOLUTION: express the following logarithmic expression as a single logarithm, then calculate its value; log4-log2+log15-log60?

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Question 767093: express the following logarithmic expression as a single logarithm, then calculate its value; log4-log2+log15-log60?

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!


Use the 2 identities:



Log a + log b = log (a*b)

Log a - log b = log (a/b)



So, log4-log2+log15-log60 = log ((4/2)*(15/60)) 



= log(1/2) = log1 - log2 = -log2 (remember that log1 = 0)



Hope you got it :)