SOLUTION: Question A) A company needs to clear 400ha of land. The company has newly acquired a D7 H bulldozer and is renting another bulldozer (D7R). A bulldozer consumes 200 litres of fuel

Algebra ->  Rate-of-work-word-problems -> SOLUTION: Question A) A company needs to clear 400ha of land. The company has newly acquired a D7 H bulldozer and is renting another bulldozer (D7R). A bulldozer consumes 200 litres of fuel       Log On


   

Question 767028: Question A) A company needs to clear 400ha of land. The company has newly acquired a D7 H bulldozer and is renting another bulldozer (D7R). A bulldozer consumes 200 litres of fuel per day and cost of fuel is 3350/litre. The two bulldozers have different conditions and work efficiency differs according to machine condition and operator. The company currently pays 1,200,000 UGX daily for the dry-hire bulldozer.
How much money will the company spend on fuel for both bulldozers to clear all the 400 hectares?

Logic and assumptions:


Question A (ii) If the cost of a new bulldozer is $120,000 advice the company on whether to buy a new bulldozer or to hire another bulldozer in addition to the two already existing bulldozers if the company needs to clear the 400 ha in a shorter time than it would take to clear this same piece of land using the above options (One hired and one company bulldozer).

Answer by akomfestus@gmail.com(1) About Me  (Show Source):
You can put this solution on YOUR website!
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YOUR ANSWER


  • This is an equation! Solutions: x=2.
  • Graphical form: Equation x%2Bx-x%2B2x=6 was fully solved.
  • Text form: x+x-x+2x=6 simplifies to 0=0
  • Cartoon (animation) form: simplify_cartoon%28+x%2Bx-x%2B2x=6+%29
    For tutors: simplify_cartoon( x+x-x+2x=6 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION

Look at .
Eliminated similar terms highlight_red%28+x+%29,highlight_red%28+x+%29,highlight_red%28+-x+%29,highlight_red%28+2%2Ax+%29 replacing them with highlight_green%28+%281%2B1-1%2B2%29%2Ax+%29
It becomes highlight_green%28+%281%2B1-1%2B2%29%2Ax+%29=6.
Look at .
Added fractions or integers together
It becomes %28highlight_green%28+3+%29%29%2Ax=6.
Look at highlight_red%28+%28highlight_red%28+3+%29%29%2Ax+%29=6.
Remove unneeded parentheses around factor highlight_red%28+3+%29
It becomes highlight_green%28+3+%29%2Ax=6.
Look at 3%2Ax=highlight_red%28+6+%29.
Moved these terms to the left highlight_green%28+-6+%29
It becomes 3%2Ax-highlight_green%28+6+%29=0.
Look at highlight_red%28+3%2Ax-6+%29=0.
Solved linear equation highlight_red%28+3%2Ax-6=0+%29 equivalent to 3*x-6 =0
It becomes highlight_green%28+0+%29=0.
Result: 0=0
This is an equation! Solutions: x=2.

Universal Simplifier and Solver


Done!