Question 76702: Please help me solve for x, y, and z.
x/2 + y/5 + z/3= 17
x/5 + y/2 + z/5= 32
x + y/3 + z/2= 30
Answer by Edwin McCravy(20060)   (Show Source):
You can put this solution on YOUR website!
x/2 + y/5 + z/3 = 17
x/5 + y/2 + z/5 = 32
x + y/3 + z/2 = 30
Multiply the first equation through by LCD 30.
30(x/2 + y/5 + z/3) = 30(17)
15x + 6y + 10z = 510
Multiply the second equation through by LCD 10.
10(x/5 + y/2 + z/5) = 10(32)
2x + 5y + 2z = 320
Multiply the third equation through by LCD 6.
6(x + y/3 + z/2) = 6(30)
6x + 2y + 3z = 180
Now the system is easy to solve because it has
only whole numbers and no fractions:
15x + 6y + 10z = 510
2x + 5y + 2z = 320
6x + 2y + 3z = 180
Can you solve it? If not post again asking how.
Answer: (x, y, z) = (10, 60, 0)
Edwin
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