SOLUTION: please help Log2 (x) + Log2 (x – 6) = 4

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: please help Log2 (x) + Log2 (x – 6) = 4      Log On


   



Question 767015: please help
Log2 (x) + Log2 (x – 6) = 4

Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!

Log2 (x) + Log2 (x – 6) = 4
Can be written as
Log2 (x * (x - 6)) = 4
So (x*(x-6) = 2^4 = 16
x%2A%28x-6%29+-+16+=+0
x%5E2+-+6%2Ax+-+16+=+0 which is a standard quadratic equation
Solving through factorization we get
%28x+-+8%29%2A%28x+%2B+2%29+=+0
x = 8 or x = -2
Taking only the positive solution, x = 8

:)