SOLUTION: During my trip to work, I spent 3/4 of the time driving on the highway, during which I covered 5/6 of the distance. My average speed on the highway was 60 miles per hour. What are

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: During my trip to work, I spent 3/4 of the time driving on the highway, during which I covered 5/6 of the distance. My average speed on the highway was 60 miles per hour. What are       Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 766839: During my trip to work, I spent 3/4 of the time driving on the highway, during which I covered 5/6 of the distance. My average speed on the highway was 60 miles per hour. What are the possible values of my average speed, in miles per hour, during the time I was not on the highway?
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
h is total time
d is total distance
ROAD______________speed_______time___________distance
Highway___________60_________(3/4)h_________(5/6)d
NonHighway________(___)______(1/4)h_________(1/6)d

ROAD______________speed_______time___________distance
Highway___________60_________(3/4)h_________(5/6)d
NonHighway________(r)______(1/4)h_________(1/6)d

Try making two equations using rate times time equals distance:
60%2A%283%2F4%29h=%285%2F6%29d and r%281%2F4%29h=%281%2F6%29d; this last equation gives an expression for unknown r.
%28d%2Fh%29%284%29%281%2F6%29=r
r=%282%2F3%29%28d%2Fh%29
But we still have three variables and two equations, just one is rearranged.

This seems an open-ended problem. Use the highway equation to eliminate either the h or the d in the r equation. You might want to pick an arbitrary value for h or d.
Work with the highway equation....
d=54%2Ah
So you can form the equation r=%282%2F3%29%2854h%2Fh%29
r=%282%2F3%29%2A54
r=36
No longer seems so open-ended. Solution method felt strange, but result is very clear.
With that result r=36 mph, you can evaluate possible averages of highway and nonhighway speeds.